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A 14-kg block rests on a level frictionless surface and is attached by a light string to a 5.0-kg hanging mass where the string passes over a massless frictionless pulley. If g=9.8 m/s2 what is the tension in the connecting string?

Respuesta :

Answer:

Explanation:

Let T be the tension in the string .

For hanging mass

net force = m₁g - T

m₁g - T = m₁a

For mass placed on horizontal plane

T = m₂a

m₁g - m₂a = m₁a

m₁g = a ( m₂ +m₁)

a = m₁g  / ( m₂ +m₁)

= 5 x 9.8 / 19

= 2.579 m /s²

m₁g - T = m₁a

T = m₁g - m₁a

= m₁ ( g - a )

= 5 ( 9.8 - 2.579)

= 36.10 N

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