contestada

The distribution of assembly times required to assemble a certain smartphone is approximately normal with
mean 46 minutes and standard deviation 0.6 minute. Of the following, which is closest to the percentage of
assembly times between 4 and 5 minutes?

Respuesta :

MathPhys

Answer:

59%

Step-by-step explanation:

I assume you mean 4.6 minutes.

Calculate the z-scores.

z = (x āˆ’ Ī¼) / Ļƒ

zā‚ = (4 āˆ’ 4.6) / 0.6

zā‚ = -1

zā‚‚ = (5 āˆ’ 4.6) / 0.6

zā‚‚ = 0.67

Use a calculator or chart to find the probability.

P(-1 < Z < 0.67) = P(Z < 0.67) āˆ’ P(Z < -1)

P(-1 < Z < 0.67) = 0.7486 āˆ’ 0.1587

P(-1 < Z < 0.67) = 0.5899

The probability is approximately 59%.

Otras preguntas