Answer:
Right
Explanation:
The given parameters are;
The soluble sulfate formed by the metal, M = MâSOâ
In the galvanic cell formed by the metal M, we have;
The concentration of MâSOâ in the left half cell = 50.0 mM = 0.05 M
The concentration of MâSOâ in the right half cell = 5.00 M
In the galvanic cell, the metal 'M' will be dissolved into the solution with lower concentration as M²⺠which is the left half cell, making the cell negative and the solution more concentrated
In the right half cell, the metal 'M²âş' in the solution will be plated unto the electrode making the solution less concentrated and the electrode in the right half cell will be the positive electrode
Therefore;
The electrode which will be positive is the electrode in the right half cell.
